dev-arm: SMMUv3, default CMDQ entries to 128

From Linux 587e6c10a7ce89a5924fdbeff2ec524fbd6a124b, SMMUv3
implementations in 64-bit platforms must report a minimum of 128 CMDQ
entries via SMMU_IDR1. Otherwise, the SMMUv3 Linux driver returns -ENXIO.

Change-Id: I304aac1b734515b3077003e8d67cc19730afc67f
Reviewed-on: https://gem5-review.googlesource.com/c/public/gem5/+/35297
Reviewed-by: Giacomo Travaglini <giacomo.travaglini@arm.com>
Maintainer: Giacomo Travaglini <giacomo.travaglini@arm.com>
Tested-by: kokoro <noreply+kokoro@google.com>
This commit is contained in:
Adrian Herrera
2020-09-29 10:31:49 +01:00
parent 87baeab20f
commit a21573cef0

View File

@@ -162,9 +162,9 @@ class SMMUv3(ClockedObject):
# [0] S2P = 0b1, Stage 2 translation supported.
smmu_idr0 = Param.UInt32(0x094C100F, "SMMU_IDR0 register");
# [25:21] CMDQS = 0b00101, Maximum number of Command queue entries
# as log 2 (entries) (0b00101 = 32 entries).
smmu_idr1 = Param.UInt32(0x00A00000, "SMMU_IDR1 register");
# [25:21] CMDQS = 0b00111, Maximum number of Command queue entries
# as log 2 (entries) (0b00111 = 128 entries).
smmu_idr1 = Param.UInt32(0x00E00000, "SMMU_IDR1 register");
smmu_idr2 = Param.UInt32(0, "SMMU_IDR2 register");
smmu_idr3 = Param.UInt32(0, "SMMU_IDR3 register");